-1,1x^2+2,2-0.3=0

Solution for -1,1x^2+2,2-0.3=0 equation:

-1.1x^2+2.2-0.3=0

We add all the numbers together, and all the variables

-1.1x^2+1.9=0

a = -1.1; b = 0; c = +1.9;
Δ = b2-4ac
Δ = 02-4·(-1.1)·1.9
Δ = 8.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{8.36}}{2*-1.1}=\frac{0-\sqrt{8.36}}{-2.2}
=-\frac{\sqrt{}}{-2.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{8.36}}{2*-1.1}=\frac{0+\sqrt{8.36}}{-2.2}
=\frac{\sqrt{}}{-2.2}
$